Creating and Executing Servlet

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Creating and Executing Servlet

The following are the steps for creating and executing a servlet in eclipse IDE.

Select File > New > Project. Then New Project window will pop up, select Tomcat Project then click Next button.

In the New Tomcat Project window, input the project name, here use "ServletDemo",then click Next button.

To make it simple, keep this as default and click Finish button.

Select WEB-INF/src in workspace and right click it and select New > File.

In the pop up window New File, input file name "SimpleServlet.java" and click Finish button.

Input the following code in to the file SimpleServlet.java and click Save button in toolbar.

import java.io.PrintWriter;

import javax.servlet.*;

public class SimpleServlet extends javax.servlet.http.HttpServlet {

public void doGet(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response) throws javax.servlet.ServletException, java.io.IOException {

performTask(request, response);

}

public void doPost(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response)

throws javax.servlet.ServletException, java.io.IOException {

performTask(request, response); }

public void performTask(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response)

{

    try

   {

       response.setContentType("text/html");

       PrintWriter out = response.getWriter();

       out.println("This is a Simple Servlet Demo");

    }catch(Throwable theException){

       theException.printStackTrace();

    }

}

}

Select WEB-INF/ in workspace and right click it and select New > File.

A New File window will pop up and input the file name "web.xml" and click Finish button.

Input the following contentinto the file web.xml.

<?xml version="1.0" encoding="UTF-8"?>

<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN" "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd">

<web-app>

    <servlet>

                <servlet-name>SimpleServlet</servlet-name>

                <servlet-class>SimpleServlet</servlet-class>

    </servlet>

    <servlet-mapping>

                <servlet-name>SimpleServlet</servlet-name>

                <url-pattern>/SimpleServlet</url-pattern>

    </servlet-mapping>

</web-app>

Press the Start Tomcat button in tool bar, after tomcat starts, open a browser and input the URL: http://localhost:8080/ServletDemo/SimpleServlet . The result will show as below: